-37x^2+56x+80=0

Solution for -37x^2+56x+80=0 equation:

-37x^2+56x+80=0

a = -37; b = 56; c = +80;
Δ = b2-4ac
Δ = 562-4·(-37)·80
Δ = 14976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14976}=\sqrt{576*26}=\sqrt{576}*\sqrt{26}=24\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-24\sqrt{26}}{2*-37}=\frac{-56-24\sqrt{26}}{-74}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+24\sqrt{26}}{2*-37}=\frac{-56+24\sqrt{26}}{-74}
$